Molar Solution Calculator
Use this tool to calculate how much solute you need for a target molar solution, and how to dilute a stock solution to a desired concentration.
1) Prepare a Solution from a Solid
2) Dilution Calculator (C₁V₁ = C₂V₂)
What Is Molarity?
Molarity is one of the most common concentration units in chemistry. It tells you how many moles of solute are present per liter of total solution. The unit is written as M (mol/L).
For example, a 1.0 M sodium chloride solution contains 1.0 mole of NaCl dissolved to make exactly 1 liter of solution. This is different from dissolving in 1 liter of water; you always bring the total solution volume to the target mark.
Core Formulas Used in This Calculator
Preparing from a Solid
- Moles needed: n = M × V
- Mass needed: m = n × molar mass
- Purity correction: mass to weigh = pure mass ÷ (purity/100)
Diluting a Stock Solution
- Dilution equation: C₁V₁ = C₂V₂
- Stock volume to use: V₁ = (C₂ × V₂) ÷ C₁
- Solvent to add: V₂ − V₁
How to Use the Calculator Correctly
For Solid Solutes
Enter your target molarity, desired final volume, and the compound molar mass if you know it. If your reagent is not 100% pure, enter the purity percentage so the mass is automatically adjusted.
After calculating, weigh the mass shown, dissolve it in less than the final volume, then transfer to a volumetric flask and fill to the mark.
For Dilutions
Enter the stock concentration (C₁), desired concentration (C₂), and final volume (V₂). The calculator returns how much stock solution to pipette and how much solvent to add.
If C₂ is greater than C₁, a simple dilution is impossible; you need a stronger stock or a different preparation method.
Worked Examples
Example 1: 0.10 M NaCl, 500 mL
Given NaCl molar mass = 58.44 g/mol:
- V = 500 mL = 0.500 L
- n = M × V = 0.10 × 0.500 = 0.050 mol
- m = n × MM = 0.050 × 58.44 = 2.922 g
You would weigh about 2.92 g NaCl and make up to 500 mL total volume.
Example 2: Dilute 12 M HCl to 1.0 M, final volume 250 mL
- V₁ = (C₂ × V₂) ÷ C₁ = (1.0 × 250) ÷ 12 = 20.83 mL
- Solvent needed ≈ 250 − 20.83 = 229.17 mL
Pipette 20.83 mL of 12 M stock and dilute to 250 mL total.
Common Mistakes to Avoid
- Mixing up mL and L during calculations.
- Forgetting to include reagent purity corrections.
- Treating final volume as solvent volume.
- Trying to make a higher concentration by dilution alone.
- Not using appropriate glassware (volumetric flask/pipette).
Lab Safety Notes
Always use PPE (gloves, goggles, lab coat) and follow your institution’s safety protocols. For corrosive acids and bases, remember: add acid to water, not water to acid. Label every solution with concentration, date, and preparer initials.
Quick FAQ
Is molarity temperature-dependent?
Yes. Because volume changes with temperature, molarity can shift slightly. Critical work should be done at controlled temperatures.
Can I use this for buffers or mixed solutes?
You can calculate each component individually, but full buffer design also requires pKa and target pH considerations.
What if my compound is a hydrate?
Use the molar mass of the hydrate form you are weighing, not the anhydrous form.
Final Takeaway
A reliable molar solution calculator helps you prepare solutions quickly and consistently. Use it to reduce unit mistakes, account for purity, and get clear dilution instructions before you begin bench work.